The shifted up sample is the x one so large mu drags the y ranks down

Let $(X_1,X_2,\dots ,X_7)$ and $(Y_1,Y_2,\dots ,Y_9)$ be two independent random samples from the continuous distribution functions $F(x-\mu )$ and $F(x-\theta )$, respectively, where $F,\mu$ and $\theta$ are all unknown. Further, let $\mu$ be the unique median of $F(x-\mu )$ and $\theta$ be the unique median of $F(x-\theta )$. Let $R_i$ be the rank of $Y_i$ in the combined sample, i = 1, 2, …, 9. For testing $H_0:\mu =\theta$ against $H_1:\mu >\theta$, the test statistic $T={\sum }_i$₌${}_1^9{R}_i$ is proposed. Then, which of the following statements are true?