The shifted up sample is the x one so large mu drags the y ranks down

Let $(X_{1}, X_{2}, \dots, X_{7})$ and $(Y_{1}, Y_{2}, \dots, Y_{9})$ be two independent random samples from the continuous distribution functions $F(x - \mu)$ and $F(x - \theta)$, respectively, where $F, \mu$ and $\theta$ are all unknown. Further, let $\mu$ be the unique median of $F(x - \mu)$ and $\theta$ be the unique median of $F(x - \theta)$. Let $R_{i}$ be the rank of $Y_{i}$ in the combined sample, i = 1, 2, …, 9. For testing $H_{0} : \mu = \theta$ against $H_{1} : \mu > \theta$, the test statistic $T = \sum_{i}$₌$_{1}^{9} R_{i}$ is proposed. Then, which of the following statements are true?