Consider the series , where . Which of the following statements is true?
CSIR NET June 2023 — Part B
All 22 Part B questions we have transcribed from this paper, of the 38 on the site for this sitting — every option and the answer key, with the reasoning for each one.
Part B
One correct option. 3 marks, −0.75 for a wrong answer.
Q1Hypothesis droppedSeries: comparison, ratio, root, Raabe, condensation, alternating, rearrangements
- A.The series is divergent.
- B.The series is convergent.
- C.The series is conditionally convergent.✓
- D.The series is absolutely convergent.
Solution
n+1−n=1/(n+1+n) decreases to 0, so the alternating series converges (Leibniz). The absolute series behaves like ∑1/(2n), which diverges. Hence conditionally convergent — option 3 is the most precise true statement (official key: 3).
Q2Limit assumed to existlimsup, liminf and subsequential limits
Which of the following assertions is correct?
- A.limsupnexp(cos((nπ+(−1)n⋅2e)/(2n)))>1.
- B.limnexp(loge((nπ2+(−1)ne2)/(7n))) does not exist.
- C.liminfnexp(sin((nπ+(−1)n⋅2e)/(2n)))<π.✓
- D.limnexp(tan((nπ2+(−1)ne2)/(7n))) does not exist.
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q3Pointwise vs uniformContinuity, uniform continuity, Lipschitz
Which one of the following functions is uniformly continuous on the interval (0, 1)?
- A.f(x) = sin(1/x)
- B.f(x) = e−1/x2✓
- C.f(x) = eˣ cos(1/x)
- D.f(x)=cosx⋅cos(π/x)
Solution
A continuous function on (0,1) is uniformly continuous iff it extends continuously to [0,1]. e−1/x2 → 0 as x → 0⁺, so it extends; the other three oscillate without a limit at 0.
Q4Invariants don't determineEigenvalues, characteristic & minimal polynomials, Cayley–Hamilton
Let A be a 3×3 real matrix whose characteristic polynomial p(T) is divisible by T2. Which of the following statements is true?
- A.The eigenspace of A for the eigenvalue 0 is two-dimensional.
- B.All the eigenvalues of A are real.✓
- C.A3=0.
- D.A is diagonalizable.
Solution
p(T)=T2(T−c) with c real (degree-3 real polynomial). So all eigenvalues are real. The geometric multiplicity of 0 may be 1 (Jordan block), so (1), (4) fail; A need not be nilpotent (c ≠ 0).
Q5Invariants don't determineEigenvalues, characteristic & minimal polynomials, Cayley–Hamilton
Let T be a linear operator on R3. Let f(X)∈R[X] denote its characteristic polynomial. Consider the following statements. (a) Suppose T is non-zero and 0 is an eigenvalue of T. If we write f(X) = X·g(X) in R[X], then the linear operator g(T) is zero. (b) Suppose 0 is an eigenvalue of T with at least two linearly independent eigenvectors. If we write f(X) = X·g(X) in R[X], then the linear operator g(T) is zero. Which of the following is true?
- A.Both (a) and (b) are true.
- B.Both (a) and (b) are false.
- C.(a) is true and (b) is false.
- D.(a) is false and (b) is true.✓
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q6Execution slipGram–Schmidt, orthogonal/unitary/normal matrices, spectral theorem
Let x=(x1,…,xn) and y=(y1,…,yn) denote vectors in Rn for a fixed n ≥ 2. Which of the following defines an inner product on Rn?
- A.⟨x, y⟩ =∑i,j=1n xiyj
- B.⟨x, y⟩ =∑i,j=1n (xi2+yj2)
- C.⟨x, y⟩ =∑j=1n j3xjyj✓
- D.⟨x, y⟩ =∑j=1n xjyn₋j₊1
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q7Property not inheritedGroup actions, class equation, p-groups
Let p be a prime number. Let G be a group such that for each g ∈ G there exists an n∈N such that gpn = 1. Which of the following statements is FALSE?
- A.If |G| =p6, then G has a subgroup of index p2.
- B.If |G| =p6, then G has at least five normal subgroups.
- C.Center of G can be infinite.
- D.There exists G with |G| =p6 such that G has exactly six normal subgroups.✓
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q8Execution slipIdeals, quotient rings, prime & maximal ideals, CRT
The number of solutions of the equation x2=1 in the ring Z/105Z is
- A.0
- B.2
- C.4
- D.8✓
Solution
By CRT, Z/105Z≅Z/3×Z/5×Z/7;x2=1 has exactly 2 solutions in each odd prime field, giving 23=8.
Q9openPolynomial rings and irreducibility tests
How many real roots does the polynomial x3+3x−2023 have?
- A.0
- B.1✓
- C.2
- D.3
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q10Finite-dimensional intuitionMeasurable sets and functions
Suppose S is an infinite set. Assuming that the axiom of choice holds, which of the following is true?
- A.S is in bijection with the set of rational numbers.
- B.S is in bijection with the set of real numbers.
- C.S is in bijection with S × S.✓
- D.S is in bijection with the power set of S.
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q11Execution slipLaurent series, classification of singularities, Casorati–Weierstrass
Let f(z)=exp(z+1/z),z∈C∖{0}. The residue of f at z = 0 is
- A.∑l=0∞ 1/(l+1)!
- B.∑l=0∞ 1/(l!(l+1))
- C.∑l=0∞ 1/(l!(l+1)!)✓
- D.∑l=0∞ 1/((l2+l)!)
Solution
Multiply the series eᶻ =∑zm/m! and e1/z =∑ z−k/k!; the coefficient of z−1 comes from k=m+1:∑m1/(m!(m+1)!).
Q12Execution slipPower series and analyticity
Consider the function f defined by f(z)=1/(1−z−z2) for z∈C such that 1−z−z2=0. Which of the following statements is true?
- A.f is an entire function.
- B.f has a simple pole at z = 0.
- C.f has a Taylor series expansion f(z)=∑anzn, where a0=1,a1=0 and an₊2=an+an₊1 for n ≥ 0.
- D.f has a Taylor series expansion f(z)=∑anzn, where a0=1,a1=1 and an₊2=an+an₊1 for n ≥ 0.✓
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q13Numerical convergenceLinear ODE, Wronskian, variation of parameters, systems
Suppose x(t) is the solution of the initial value problem in R2: ẋ = Ax, x(0)=x0, where A = [[5, 4], [1, 2]]. Which of the following statements is true?
- A.x(t) is a bounded solution for some x0=0.
- B.e−6t|x(t)| → 0 as t→∞, for all x0=0.
- C.e−t|x(t)| →∞ as t→∞, for all x0=0.
- D.e−10t|x(t)| → 0 as t→∞, for all x0=0.✓
Solution
Eigenvalues of A are 6 and 1 (trace 7, det 6), both positive: every non-zero solution grows like e6t or et. So (1) fails, (2) fails along the 6-eigendirection, (3) fails along the 1-eigendirection, and (4) holds since 10 > 6.
Q14Execution slipFirst-order PDE: Lagrange, Charpit, characteristics
Let u(x, y) be the solution of the Cauchy problem u⋅ux+uy=0 for x∈R,y>0, with u(x, 0) = x for x∈R. Which of the following is the value of u(2, 3)?
- A.2
- B.3
- C.1/2✓
- D.1/3
Solution
Characteristics: dx/dy = u with u constant along them, so x=x0+u⋅y and u=x0. Hence u = x/(1 + y), and u(2, 3) = 1/2.
Q15Hypothesis droppedEuler–Lagrange equation and standard functionals
Consider the variational problem (P):J(y)=∫01[(y′)2−y|y|·y′ + xy] dx, y(0) = 0, y(1) = 0. Which of the following statements is correct?
- A.(P) has no stationary function (extremal).
- B.y ≡ 0 is the only stationary function (extremal) for (P).
- C.(P) has a unique stationary function (extremal) y not identically equal to 0.✓
- D.(P) has infinitely many stationary functions (extremals).
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q16Execution slipFredholm and Volterra equations
For the unknown y:[0,1]→R, consider the boundary value problem y″(x) + 2y(x) = 0 for x ∈ (0,1), y(0) = y(1) = 0. It is given that it corresponds to the integral equation y(x)=2∫01K(x,t)y(t) dt. Which of the following is the kernel K(x, t)?
- A.K(x,t) = t(1 − x) for t < x; x(1 − t) for t > x✓
- B.K(x,t)=t2(1−x) for t<x;x2(1−t) for t > x
- C.K(x,t)=t(1−x) for t<x;x(1−t) for t > x
- D.K(x,t)=t3(1−x) for t<x;x3(1−t) for t > x
Solution
The Green's function of −y″ with Dirichlet conditions on [0,1] is G(x,t) = t(1 − x) for t < x and x(1 − t) for t > x; then y=2∫Gy.
Q17Execution slipStandard discrete and continuous distributions
Let X1,X2,X3,X4 be i.i.d. Bernoulli(1/3) and X(1)≤⋯≤X(4) the order statistics. Which of the following is true?
- A.X(1) and X(4) are independent.
- B.Expectation of X(2) is 1/2.
- C.Variance of X(2) is 8/81.✓
- D.X(4) is a degenerate random variable.
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q18openSufficiency, completeness, UMVUE, Cramér–Rao
Let X be a Poisson random variable with mean λ. Which of the following parametric functions is not estimable?
- A.λ⁻1✓
- B.λ
- C.λ2
- D.e−λ
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q19Execution slipLikelihood ratio and standard tests
Let X1,…,X7 and Y1,…,Y9 be independent random samples from continuous CDFs F and G. For the Wald–Wolfowitz run test of H0:F=G vs H1:F=G, let R be the total number of runs in the combined ordered arrangement. Which of the following is true?
- A.PH0(R = 6) = 28/286, PH0(R = 9) = 28/143.
- B.PH0(R = 6) = 21/286, PH0(R = 9) = 15/286.
- C.PH0(R = 6) = 21/286, PH0(R = 9) = 28/143.✓
- D.PH0(R = 6) = 21/286, PH0(R = 9) = 15/286.
Trap Analysis has the working, and why each of the other options was written to tempt you.
Q20Execution slipGauss–Markov, regression, ANOVA basics
Consider the simple linear regression model Yi=βxi+εi,i=1,…,n, where E(εi)=0,Cov(εi,εk)=0 for i ≠ k and Var(εi)=xi2σ2. The best linear unbiased estimator of β is
- A.∑Yixi/∑xi2
- B.∑Yi/∑xi
- C.(1/n)∑Yi/xi✓
- D.(1/n)∑Yixi/xi2
Solution
Heteroscedastic errors: divide by xi to get Yi/xi=β+εi/xi with constant variance σ2; the BLUE is the plain mean of Yi/xi(weighted least squares with weights 1/xi2).
Q21openMultivariate normal distribution
Let X=(X1,X2)T be bivariate normal with mean (0, 0)ᵀ and covariance ∑=[[5,−3],[−3,10]]. The mean vector and covariance matrix of Y=(X1,5−2X2)T are
- A.(0, 5)ᵀ, [[5, −3], [−3, 40]]
- B.(0, 5)ᵀ, [[5, −6], [−6, 20]]
- C.(0, 5)ᵀ, [[5, 3], [3, 20]]
- D.(0, 5)ᵀ, [[5, 6], [6, 40]]✓
Solution
E[5−2X2]=5;Var(5−2X2)=4⋅10=40;Cov(X1,5−2X2)=−2⋅(−3)=6.
Q22Execution slipMultivariate normal distribution
Suppose X=(X1,X2,X3,X4)T ~ N4(0,I2 ⊗ ∑) with ∑=[[2,−1],[−1,2]]. Define Z=[[X1,X2],[X3,X4]] and Q = ZᵀZ. If Wm(n,∑) denotes a Wishart distribution of order m with n degrees of freedom, the distribution of Q11+Q12+Q21+Q22 is
- A.W1(2,2)✓
- B.W1(1,2)
- C.W1(2,1)
- D.2χ42
Trap Analysis has the working, and why each of the other options was written to tempt you.